JAMB 1983 · UME · Q42

Simplify $\sqrt[3]{\dfrac{27a^9}{8}}$ .

Worked solution (try it first)

A cube root can be taken of each part separately: $\sqrt[3]{27} = 3$ , because $3^3 = 27$ , and $\sqrt[3]{8} = 2$ .
For the power, divide the index by 3: $\sqrt[3]{a^9} = a^{9 \div 3} = a^3$ .
So the result is $\dfrac{3a^3}{2}$ , option E.