JAMB 1984 · UME · Q42

Find the $x$ -coordinates of the points of intersection of $y = 2x + 1$ and $y = x^2 - 2x + 1$ shown in the graph.

The vertical scale is 0.4 of the horizontal scale.

Worked solution (try it first)

At the points where the graphs meet, the $y$ -values are equal: $x^2 - 2x + 1 = 2x + 1$ .
Bring everything to one side: $x^2 - 4x = 0$ .
Factorise: $x(x - 4) = 0$ , so $x = 0$ or $x = 4$ , option E.