JAMB 1984 · UME · Q44

In the figure, ∠TSP=∠PRQ\angle TSP = \angle PRQ, QR=8QR = 8 cm, PR=6PR = 6 cm and ST=12ST = 12 cm. Find the length SPSP.

8 cm6 cm12 cmPQRST
Worked solution (try it first)
  1. Triangles PRQPRQ and PSTPST share ∠P\angle P and have ∠PRQ=∠PST\angle PRQ = \angle PST, so they are similar, with RR matching SS and QQ matching TT.
  2. Corresponding sides are in the same ratio: PRPS=QRTS\dfrac{PR}{PS} = \dfrac{QR}{TS}, so 6SP=812\dfrac{6}{SP} = \dfrac{8}{12}.
  3. Cross-multiply: 8×SP=728 \times SP = 72, so SP=9SP = 9 cm, option C.

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