JAMB 1985 · UME · Q34

Without using tables, calculate the value of 1+sec⁡230∘1 + \sec^2 30^\circ.

Worked solution (try it first)
  1. sec⁡30∘=1cos⁡30∘\sec30^\circ = \dfrac{1}{\cos30^\circ}
    =13/2= \dfrac{1}{\sqrt3/2}
    =23= \dfrac{2}{\sqrt3}.
  2. Square it: sec⁡230∘=43\sec^2 30^\circ = \dfrac{4}{3}.
  3. Add 1: 1+43=73=2131 + \frac43 = \frac73 = 2\frac13, option A.

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