JAMB 1987 · UME · Q32

In the diagram, QR∥TSQR \parallel TS and QR:TS=2:3QR : TS = 2 : 3. Find the ratio of the area of triangle PQRPQR to the area of the trapezium QRSTQRST.

PTSQR
Worked solution (try it first)
  1. QR∥TSQR \parallel TS, so triangles PQRPQR and PTSPTS are similar with lengths in the ratio 2:32 : 3.
  2. Areas of similar figures are in the ratio of the squares of the lengths: 22:32=4:92^2 : 3^2 = 4 : 9.
  3. The trapezium is the big triangle minus the small one: 9−4=59 - 4 = 5 parts.
  4. So the ratio is 4:54 : 5, option B.

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