JAMB 1988 · UME · Q22✱✱

The solution of the quadratic equation $px^2 + qx + b = 0$ is

Worked solution (try it first)

Match $px^2 + qx + b = 0$ with $ax^2 + bx + c = 0$ : the $x^2$ coefficient is $p$ , the $x$ coefficient is $q$ and the constant is $b$ .
The formula is $x = \dfrac{-(x\text{ coefficient}) \pm \sqrt{(x\text{ coefficient})^2 - 4(x^2\text{ coefficient})(\text{constant})}}{2(x^2\text{ coefficient})}$ .
Put in $q$ , $p$ and $b$ : $x = \dfrac{-q \pm \sqrt{q^2 - 4bp}}{2p}$ , option C.