JAMB 1988 · UME · Q44

A metal pipe 10 cm long has an external diameter of 12 cm and a thickness of 1 cm. Find the volume of the metal used in making the pipe.

Worked solution (try it first)
  1. External radius: 12÷2=612 \div 2 = 6 cm.
  2. The wall is 1 cm thick, so the internal radius is 6−1=56 - 1 = 5 cm.
  3. The metal is the ring between the circles times the length: π(62−52)×10\pi(6^2 - 5^2) \times 10.
  4. That is π×11×10=110π cm3\pi \times 11 \times 10 = 110\pi\text{ cm}^3, option B.

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