JAMB 1988 · UME · Q45

Solid mensuration

A solid consists of a hemisphere surmounted by a right circular cone, both of radius 3.0 cm; the cone has height 6.0 cm. Find the volume of the solid.

Worked solution (try it first)

Hemisphere: half of $\frac43\pi r^3$ , which is $\frac23\pi \times 27 = 18\pi\text{ cm}^3$ .
Cone: $\frac13\pi r^2h = \frac13\pi \times 9 \times 6$
$= 18\pi\text{ cm}^3$ .
Total: $18\pi + 18\pi = 36\pi\text{ cm}^3$ , option B.

Report a problem with this question