JAMB 1989 · UME · Q25

Find the range of values of rr which satisfies ra+rb+rc>1\frac ra + \frac rb + \frac rc > 1, where aa, bb and cc are positive.

Worked solution (try it first)
  1. Take rr out as a common factor: r(1a+1b+1c)>1r\left(\frac1a + \frac1b + \frac1c\right) > 1.
  2. Add the fractions over the common denominator abcabc: 1a+1b+1c=bc+ac+ababc\frac1a + \frac1b + \frac1c = \dfrac{bc + ac + ab}{abc}.
  3. This fraction is positive, since aa, bb and cc are, so dividing by it keeps the sign: r>abcbc+ac+abr > \dfrac{abc}{bc + ac + ab}, option A.

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