QuestionJAMBGeneral Maths1990ObjectiveQuadratics & their graphsQuadratics & their graphs
The H.C.F. of a2bx+abx2 and a2b−b3 is
Worked solution (try it first)
Factorise the first:
a2bx+abx2=abx(a+x).
Factorise the second:
a2b−b3=b(a2−b2)=b(a−b)(a+b).
The only factor in both is
b, so the H.C.F. is
b, option A.
Report a problem with this question