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JAMB 1990 · UME · Q3

Correct 241.34×(3×10−3)2241.34 \times (3 \times 10^{-3})^2 to 4 significant figures.

Worked solution (try it first)
  1. Square the bracket: (3×10−3)2=9×10−6(3 \times 10^{-3})^2 = 9 \times 10^{-6}, squaring both the 3 and the power.
  2. Multiply: 241.34×9=2172.06241.34 \times 9 = 2172.06, so the value is 2172.06×10−6=0.002172062172.06 \times 10^{-6} = 0.00217206.
  3. To 4 significant figures (starting from the 2), this is 0.002172, option D.

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