JAMB 1991 · UME · Q21

Find the range of values of xx which satisfy the inequality x2+x3+x4<1\frac x2 + \frac x3 + \frac x4 < 1.

Worked solution (try it first)
  1. Multiply every term by 12, the LCM of 2, 3 and 4: 6x+4x+3x<126x + 4x + 3x < 12.
  2. Collect the terms: 13x<1213x < 12.
  3. Divide by 13: x<1213x < \frac{12}{13}, option A.

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