JAMB 1991 · UME · Q25✱✱

Evaluate x2(x2−1)−12−(x2−1)12x^2(x^2 - 1)^{-\frac12} - (x^2 - 1)^{\frac12}.

Worked solution (try it first)
  1. Write the second term with the same factor: (x2−1)12=(x2−1)×(x2−1)−12(x^2 - 1)^{\frac12} = (x^2 - 1) \times (x^2 - 1)^{-\frac12}.
  2. Take out (x2−1)−12(x^2 - 1)^{-\frac12}: the expression is (x2−1)−12[x2−(x2−1)](x^2 - 1)^{-\frac12}\left[x^2 - (x^2 - 1)\right].
  3. The bracket is x2−x2+1=1x^2 - x^2 + 1 = 1, so the result is (x2−1)−12(x^2 - 1)^{-\frac12}, option D.

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