JAMB 1992 · UME · Q19

What is the nnth term of the sequence 2,6,12,20,…2, 6, 12, 20, \dots?

Worked solution (try it first)
  1. Write each term as a product of two consecutive whole numbers: 2=1×22 = 1 \times 2, 6=2×36 = 2 \times 3, 12=3×412 = 3 \times 4, 20=4×520 = 4 \times 5.
  2. The nnth term is n(n+1)=n2+nn(n + 1) = n^2 + n.
  3. Check n=3n = 3: 9+3=129 + 3 = 12.
  4. So the answer is option C.

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