JAMB 1992 · UME · Q20

For an arithmetic sequence, the first term is 2 and the common difference is 3. Find the sum of the first 11 terms.

Worked solution (try it first)
  1. Use Sn=n2(2a+(n−1)d)S_n = \frac n2\big(2a + (n - 1)d\big) with a=2a = 2, d=3d = 3 and n=11n = 11.
  2. The bracket is 2×2+10×3=4+30=342 \times 2 + 10 \times 3 = 4 + 30 = 34.
  3. So S11=112×34=187S_{11} = \frac{11}{2} \times 34 = 187, option B.

Report a problem with this question