JAMB 1992 · UME · Q33

Find the equation of the line through (5,7)(5, 7) parallel to the line 7x+5y=127x + 5y = 12.

Worked solution (try it first)
  1. Parallel lines have the same gradient, so the new line keeps the same left-hand side: 7x+5y=k7x + 5y = k.
  2. Put in the point (5,7)(5, 7): k=7(5)+5(7)=35+35=70k = 7(5) + 5(7) = 35 + 35 = 70.
  3. So the line is 7x+5y=707x + 5y = 70, option B.

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