JAMB 1992 · UME · Q43

If the mean of the frequency distribution below is 5.2, find yy.

xx 2 4 6 8
ff 4 yy 6 5
Worked solution (try it first)
  1. Total frequency: 4+y+6+5=15+y4 + y + 6 + 5 = 15 + y.
  2. Total of fxfx: 8+4y+36+40=84+4y8 + 4y + 36 + 40 = 84 + 4y.
  3. Mean =∑fx∑f= \frac{\sum fx}{\sum f}, so 84+4y15+y=5.2\frac{84 + 4y}{15 + y} = 5.2 and 84+4y=78+5.2y84 + 4y = 78 + 5.2y.
  4. Collect terms: 6=1.2y6 = 1.2y, so y=5.0y = 5.0, option C.

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