JAMB 1992 · UME · Q44

Find the mode and median respectively of the distribution below.

No. of children 0 1 2 3 4 5 6
No. of families 7 11 6 7 7 5 3
Worked solution (try it first)
  1. The mode is the number of children with the most families: 1 child, 11 families.
  2. There are 7+11+6+7+7+5+3=467 + 11 + 6 + 7 + 7 + 5 + 3 = 46 families, so the median is halfway between the 23rd and 24th.
  3. Running totals: 7, 18, 24.
  4. The 19th to 24th families all have 2 children, so the median is 2.
  5. So the mode and median are 1 and 2, option B.

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