JAMB 1994 · UME · Q2✱✱

Evaluate (0.36×5.4×0.63)÷(4.2×9.0×2.4)(0.36 \times 5.4 \times 0.63) \div (4.2 \times 9.0 \times 2.4), correct to 2 significant figures.

Worked solution (try it first)
  1. Top: 0.36×5.4=1.9440.36 \times 5.4 = 1.944, and 1.944×0.63=1.224721.944 \times 0.63 = 1.22472.
  2. Bottom: 4.2×9.0=37.84.2 \times 9.0 = 37.8, and 37.8×2.4=90.7237.8 \times 2.4 = 90.72.
  3. Divide: 1.22472÷90.72=0.01351.22472 \div 90.72 = 0.0135.
  4. The third significant figure is 5, so round up: 0.014, option B.

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