JAMB 1994 · UME · Q3

Evaluate log⁡50.04log⁡318−log⁡32\dfrac{\log_5 0.04}{\log_3 18 - \log_3 2}.

Worked solution (try it first)
  1. 0.04=125=5−20.04 = \frac{1}{25} = 5^{-2}, so log⁡50.04=−2\log_5 0.04 = -2.
  2. Subtracting logs divides: log⁡318−log⁡32=log⁡39=2\log_3 18 - \log_3 2 = \log_3 9 = 2.
  3. So the value is −22=−1\frac{-2}{2} = -1, option B.

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