JAMB 1994 · UME · Q32

A triangle has base 7 cm and other sides 6 cm and 5 cm. Find its height hh onto the base.

h6 cm5 cm7 cm
Worked solution (try it first)
  1. Find the area with Heron's formula.
  2. The semi-perimeter is s=7+6+52=9s = \frac{7 + 6 + 5}{2} = 9.
  3. Area =s(s−a)(s−b)(s−c)= \sqrt{s(s - a)(s - b)(s - c)}, which is 9×2×3×4=216\sqrt{9 \times 2 \times 3 \times 4} = \sqrt{216}.
  4. As 216=36×6216 = 36 \times 6, the area is 66 cm26\sqrt6\text{ cm}^2.
  5. Area =12×= \frac12 \times base ×\times height, so 12×7×h=66\frac12 \times 7 \times h = 6\sqrt6 and h=1267h = \frac{12\sqrt6}{7}
    =1276= \frac{12}{7}\sqrt6 cm, option B.

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