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JAMB 1995 · UME · Q15

Factorize completely the expression abx2+6y−3ax−2byxabx^2 + 6y - 3ax - 2byx.

Worked solution (try it first)
  1. Group the terms with axax and those with yy: (abx2−3ax)−(2bxy−6y)(abx^2 - 3ax) - (2bxy - 6y).
  2. Take out the common factors: ax(bx−3)−2y(bx−3)ax(bx - 3) - 2y(bx - 3).
  3. Take out the common bracket: (ax−2y)(bx−3)(ax - 2y)(bx - 3), option A.

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