JAMB 1995 · UME · Q42

The frequency distribution below shows the ages of students in a secondary school. In a pie chart of the data, the angle for the 15-year-olds is

Age in years	13	14	15	16	17
No. of students	3	10	30	42	15

Worked solution (try it first)

Total students: $3 + 10 + 30 + 42 + 15 = 100$ .
The 15-year-olds' share: $\frac{30}{100} \times 360^\circ = 108^\circ$ , option D.