JAMB 1995 · UME · Q41

Find the area bounded by the curve y=3x2−2x+1y = 3x^2 - 2x + 1, the ordinates x=1x = 1 and x=3x = 3, and the xx-axis.

Worked solution (try it first)
  1. The area is ∫13(3x2−2x+1) dx=[x3−x2+x]13\int_1^3 (3x^2 - 2x + 1)\,dx = \left[x^3 - x^2 + x\right]_1^3.
  2. At x=3x = 3: 27−9+3=2127 - 9 + 3 = 21.
  3. At x=1x = 1: 1−1+1=11 - 1 + 1 = 1.
  4. Subtract: 21−1=2021 - 1 = 20, option D.

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