QuestionJAMBGeneral Maths1997ObjectiveBinary operationsBinary operations
Two binary operations ∗ and ⊕ are defined by m∗n=mn−n−1 and m⊕n=mn+n−2 for all real numbers m, n. Find the value of 3⊕(4∗5).
Worked solution (try it first)
Work out the bracket with the
∗ rule:
4∗5=4×5−5−1=14.
Now use the
⊕ rule with
m=3 and
n=14:
3⊕14=3×14+14−2.
That is
42+14−2=54, option C.
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