JAMB 1997 · UME · Q48

Find the difference between the range and the variance of the numbers 4, 9, 6, 3, 2, 8, 10, 5, 6, 7, where ∑d2=60\sum d^2 = 60.

Worked solution (try it first)
  1. The range is the largest number minus the smallest: 10−2=810 - 2 = 8.
  2. The mean is 6010=6\frac{60}{10} = 6 and ∑d2=60\sum d^2 = 60 is given, so the variance is 6010=6\frac{60}{10} = 6.
  3. The difference is 8−6=28 - 6 = 2, option A.

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