JAMB 1997 · UME · Q49

In a basket of fruits, there are 6 grapes, 11 bananas and 13 oranges. If one fruit is chosen at random, what is the probability that it is either a grape or a banana?

Worked solution (try it first)
  1. There are 6+11+13=306 + 11 + 13 = 30 fruits.
  2. A grape or a banana is 6+11=176 + 11 = 17 fruits, since one fruit can't be both.
  3. So the probability is 1730\frac{17}{30}, option A.

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