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JAMB 1997 · UME · Q50

A number is selected at random between 10 and 20, both numbers inclusive. Find the probability that the number is even.

Worked solution (try it first)
  1. From 10 to 20 inclusive there are 11 numbers.
  2. The even ones are 10, 12, 14, 16, 18, 20, which is 6 numbers.
  3. So the probability is 611\frac{6}{11}, option C.

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