JAMB 1998 · UME · Q33

Coordinate geometry

The midpoint of the segment of the line $y = 4x + 3$ which lies between the $x$ -axis and the $y$ -axis is

Worked solution (try it first)

It meets the $x$ -axis where $y = 0$ : $4x + 3 = 0$ , so $x = -\frac34$ .
That end is $\left(-\frac34, 0\right)$ .
It meets the $y$ -axis where $x = 0$ : $y = 3$ .
That end is $(0, 3)$ .
Average the ends: $\left(-\frac38, \frac32\right)$ , option D.

Report a problem with this question