JAMB 2014 · UTME · Q35

Calculate the midpoint of the segment of the line $y - 4x + 3 = 0$ which lies between the $x$ -axis and the $y$ -axis.

Worked solution (try it first)

Write the line as $y = 4x - 3$ .
It meets the $x$ -axis where $y = 0$ : $4x = 3$ , so $x = \frac34$ , giving $\left(\frac34, 0\right)$ .
It meets the $y$ -axis at $(0, -3)$ .
Average the two points: $\left(\frac38, -\frac32\right)$ , option B.