JAMB 1999 · UME · Q20

The sum of two numbers is twice their difference. If the difference of the numbers is pp, find the larger of the two numbers.

Worked solution (try it first)
  1. Let the numbers be aa (larger) and bb.
  2. The difference is a−b=pa - b = p, and the sum is twice that: a+b=2pa + b = 2p.
  3. Add the two equations so bb cancels: 2a=3p2a = 3p.
  4. So the larger number is a=3p2a = \frac{3p}{2}, option B.

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