JAMB 1999 · UME · Q47

The marks scored by students in a test are given below. Find the median.

Marks 0 1 2 3 4 5 6 7 8 9 10
No. of students 2 2 11 10 16 51 40 10 25 15 20
Worked solution (try it first)
  1. Total students: 2+2+11+10+16+51+40+10+25+15+20=2022 + 2 + 11 + 10 + 16 + 51 + 40 + 10 + 25 + 15 + 20 = 202, so the median is halfway between the 101st and 102nd marks.
  2. Running totals: 2, 4, 15, 25, 41, 92 (mark 5), 132 (mark 6).
  3. The 93rd to 132nd students all scored 6, so the 101st and 102nd are both 6: the median is 6, option B.

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