JAMB 2000 · UME · Q34

The diagram shows the graph of $y = x^2$ . Find the area of the shaded region, under the curve between $x = 0$ and $x = 4$ .

The vertical scale is one fifth of the horizontal scale.

Worked solution (try it first)

The area under the curve is $\int_0^4 x^2\,dx = \left[\frac{x^3}{3}\right]_0^4$ .
That is $\frac{64}{3} - 0 = \frac{64}{3}$ square units, option C.