QuestionJAMBGeneral Maths2000ObjectiveCalculus (JAMB bridge)Calculus (JAMB bridge)
If y=2xcos2x−sin2x, find dxdy when x=4π.
Worked solution (try it first)
Product rule on
2xcos2x:
2cos2x+2x(−2sin2x)=2cos2x−4xsin2x.
Chain rule on
sin2x:
2cos2x.
Subtract it:
dxdy=−4xsin2x.
At
x=4π,
sin2x=sin2π=1, so
dxdy=−4×4π
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