JAMB 2000 · UME · Q36

If y=2xcos⁡2x−sin⁡2xy = 2x\cos2x - \sin2x, find dydx\frac{dy}{dx} when x=π4x = \frac\pi4.

Worked solution (try it first)
  1. Product rule on 2xcos⁡2x2x\cos2x: 2cos⁡2x+2x(−2sin⁡2x)=2cos⁡2x−4xsin⁡2x2\cos2x + 2x(-2\sin2x) = 2\cos2x - 4x\sin2x.
  2. Chain rule on sin⁡2x\sin2x: 2cos⁡2x2\cos2x.
  3. Subtract it: dydx=−4xsin⁡2x\frac{dy}{dx} = -4x\sin2x.
  4. At x=π4x = \frac\pi4, sin⁡2x=sin⁡π2=1\sin2x = \sin\frac\pi2 = 1, so dydx=−4×π4\frac{dy}{dx} = -4 \times \frac\pi4
    =−π= -\pi, option B.

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