JAMB 2000 · UME · Q39

A function f(x)f(x) passes through the origin and its first derivative is 3x+23x + 2. What is f(x)f(x)?

Worked solution (try it first)
  1. Integrate the derivative: f(x)=32x2+2x+cf(x) = \frac32x^2 + 2x + c.
  2. The curve passes through the origin, so f(0)=0f(0) = 0 and c=0c = 0.
  3. So y=32x2+2xy = \frac32x^2 + 2x, option A.

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