JAMB 2000 · UME · Q40

The expression ax2+bx+cax^2 + bx + c equals 5 at x=1x = 1. If its derivative is 2x+12x + 1, what are the values of aa, bb, cc respectively?

Worked solution (try it first)
  1. The derivative of ax2+bx+cax^2 + bx + c is 2ax+b2ax + b.
  2. Match it with 2x+12x + 1: 2a=22a = 2 and b=1b = 1, so a=1a = 1 and b=1b = 1.
  3. At x=1x = 1 the expression is a+b+c=5a + b + c = 5, so 1+1+c=51 + 1 + c = 5 and c=3c = 3.
  4. So aa, bb, cc are 1, 1, 3, option D.

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