JAMB 2001 · UME · Q19

Evaluate ∣−1−1−1311121∣\begin{vmatrix} -1 & -1 & -1 \\ 3 & 1 & 1 \\ 1 & 2 & 1 \end{vmatrix}.

Worked solution (try it first)
  1. Expand along the first row, with signs +  −  ++ \; - \; +.
  2. The minor of the first entry is 1×1−1×2=−11 \times 1 - 1 \times 2 = -1, so the first term is (−1)(−1)=1(-1)(-1) = 1.
  3. The minor of the second entry is 3×1−1×1=23 \times 1 - 1 \times 1 = 2.
  4. With the minus sign, the term is −(−1)(2)=2-(-1)(2) = 2.
  5. The third term is −1×(3×2−1×1)=−5-1 \times (3 \times 2 - 1 \times 1) = -5.
  6. Add them: 1+2−5=−21 + 2 - 5 = -2, option B.

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