QuestionJAMBGeneral Maths2001ObjectiveMatrices & determinantsMatrices & determinants
Evaluate −131−112−111.
Worked solution (try it first)
Expand along the first row, with signs
+−+.
The minor of the first entry is
1×1−1×2=−1, so the first term is
(−1)(−1)=1.
The minor of the second entry is
3×1−1×1=2.
With the minus sign, the term is
−(−1)(2)=2.
The third term is
−1×(3×2−1×1)=−5.
Add them:
1+2−5=−2, option B.
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