JAMB 2001 · UME · Q18

Given the matrix K=(2134)K = \begin{pmatrix} 2 & 1 \\ 3 & 4 \end{pmatrix}, the matrix K2+K+IK^2 + K + I, where II is the 2×22 \times 2 identity matrix, is

Worked solution (try it first)
  1. K2K^2 means K×KK \times K, row by column: K2=(4+32+46+123+16)K^2 = \begin{pmatrix} 4 + 3 & 2 + 4 \\ 6 + 12 & 3 + 16 \end{pmatrix}
    =(761819)= \begin{pmatrix} 7 & 6 \\ 18 & 19 \end{pmatrix}.
  2. Add KK entry by entry: (972123)\begin{pmatrix} 9 & 7 \\ 21 & 23 \end{pmatrix}.
  3. II adds 1 to each diagonal entry only: (1072124)\begin{pmatrix} 10 & 7 \\ 21 & 24 \end{pmatrix}, option B.

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