JAMB 2001 · UME · Q23

Solid mensuration

A cylindrical tank has a capacity of $3080\text{ m}^3$ . What is the depth of the tank if the diameter of its base is 14 m? $\left[\pi = \frac{22}{7}\right]$

Worked solution (try it first)

Radius $= 14 \div 2 = 7$ m, so the base area is $\frac{22}{7} \times 49 = 154\text{ m}^2$ .
Volume = base area × depth: $154h = 3080$ .
So $h = 3080 \div 154 = 20$ m, option A.

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