JAMB 2001 · UME · Q24

A sector of a circle of radius 7.2 cm which subtends an angle of 300∘300^\circ at the centre is used to form a cone. What is the radius of the base of the cone?

Worked solution (try it first)
  1. The arc of the sector becomes the circumference of the base: 300360×2π×7.2=2πr\frac{300}{360} \times 2\pi \times 7.2 = 2\pi r.
  2. Divide both sides by 2π2\pi: r=7.2×56=6r = 7.2 \times \frac56 = 6 cm, option A.

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