QuestionJAMBGeneral Maths2001ObjectiveApproximation & errorApproximation & error
Evaluate 21.05347−1.6324×0.43, to 3 decimal places.
Worked solution (try it first)
Multiply before subtracting:
1.6324×0.43=0.701932.
Subtract:
21.05347−0.701932=20.351538.
To 3 decimal places, the fourth decimal is 5, so round up: 20.352, option B.
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