JAMB 2001 · UME · Q4

Approximation & error

Evaluate $\dfrac{(0.14)^2 \times 0.275}{7 \times 0.02}$ correct to 3 decimal places.

Worked solution (try it first)

Square: $(0.14)^2 = 0.0196$ .
Then $0.0196 \times 0.275 = 0.00539$ .
Bottom: $7 \times 0.02 = 0.14$ .
Divide: $0.00539 \div 0.14 = 0.0385$ .
The fourth decimal is 5, so round up: 0.039, option B.

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