JAMB 2002 · UME · Q23Dispersion & cumulative frequencyThe range of the data k+2,k−3,k+4,k−2,k,k−5,k+3,k−1k + 2, k - 3, k + 4, k - 2, k, k - 5, k + 3, k - 1k+2,k−3,k+4,k−2,k,k−5,k+3,k−1 and k+6k + 6k+6 isA6B8C10D11Worked solution (try it first)The largest value is k+6k + 6k+6 and the smallest is k−5k - 5k−5.The range is (k+6)−(k−5)(k + 6) - (k - 5)(k+6)−(k−5).The kkk terms cancel, leaving 6+5=116 + 5 = 116+5=11, option D.Report a problem with this question