JAMB 2003 · UME · Q13

The sum of the first nn terms of an arithmetic progression is 252. If the first term is −16-16 and the last term is 72, find the number of terms.

Worked solution (try it first)
  1. When you know the first and last terms, Sn=n2(a+l)S_n = \frac n2(a + l).
  2. So n2(−16+72)=252\frac n2(-16 + 72) = 252, which is 28n=25228n = 252.
  3. Divide both sides by 28: n=9n = 9, option B.

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