JAMB 2003 · UME · Q24

The locus of a point PP which moves on one side only of a straight line XYXY so that ∠XPY=90∘\angle XPY = 90^\circ is

Worked solution (try it first)
  1. The angle in a semicircle is a right angle, so if ∠XPY=90∘\angle XPY = 90^\circ then PP lies on the circle with diameter XYXY.
  2. PP stays on one side of XYXY, so it traces only half of that circle: a semicircle, option C.

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