JAMB 2003 · UME · Q49

Find the number of committees of three that can be formed consisting of two men and one woman from four men and three women.

Worked solution (try it first)
  1. Two men from four: 4C2=6^4C_2 = 6 ways.
  2. One woman from three: 3C1=3^3C_1 = 3 ways.
  3. Each pair of men can go with each woman, so multiply: 6×3=186 \times 3 = 18, option B.

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