JAMB 2003 · UME · Q50

Statistics: data & averages

By how much is the mean of 30, 56, 31, 55, 43 and 44 less than the median?

Worked solution (try it first)

The numbers add up to 259, so the mean is $\frac{259}{6} \approx 43.17$ .
In order: 30, 31, 43, 44, 55, 56.
The median is halfway between the 3rd and 4th: $\frac{43 + 44}{2} = 43.5$ .
The difference is $43.5 - 43.17 = 0.33$ , option D.

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