Stepwise
Start practisingPractise

JAMB 2004 · UME · Q13

Factorize completely ac−2bc−a2+4b2ac - 2bc - a^2 + 4b^2.

Worked solution (try it first)
  1. Group the first two and last two terms: c(a−2b)−(a2−4b2)c(a - 2b) - (a^2 - 4b^2).
  2. Factorise the difference of two squares: a2−4b2=(a−2b)(a+2b)a^2 - 4b^2 = (a - 2b)(a + 2b).
  3. Take out the common bracket: (a−2b)[c−(a+2b)]=(a−2b)(c−a−2b)(a - 2b)[c - (a + 2b)] = (a - 2b)(c - a - 2b), option B.

Report a problem with this question