JAMB 2004 · UME · Q16

The shaded area in the diagram is represented by

The vertical scale is half the horizontal scale.

Worked solution (try it first)

The line through $(0, 6)$ and $(2, 0)$ has gradient $\frac{0 - 6}{2 - 0} = -3$ and $y$ -intercept 6, so $y = -3x + 6$ , that is $y + 3x = 6$ .
The shaded side contains the origin, where $y + 3x = 0 < 6$ .
So the region is $y + 3x < 6$ , option A.