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JAMB 2004 · UME · Q45

Find the mean deviation of 1, 2, 3 and 4.

Worked solution (try it first)
  1. The mean of 1, 2, 3, 4 is 2.5.
  2. The distances from 2.5 are 1.5, 0.5, 0.5 and 1.5, which add up to 4.
  3. The mean deviation is 44=1.0\frac44 = 1.0, option A.

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